NBA News: Schroder Chooses Wisely, Signing With Celtics To Prove He Is Worth Big Money

With not much option, Dennis Schroder has reportedly agreed to play for the Boston Celtics this 2021-22 NBA season. However, he will only make $5.9 million for the coming season – a far cry from his ambitious $25 million a year dream deal.

It was the best option for Schroder for now with no other team expressing interest in the German guard. The amount of money he will make is drastically low considering the Los Angeles Lakers had offered him an $84 million contract last season.

Schroder’s move to the Celtics was first reported by Adrian Wojnarowski on Instagram.

If it is any consolation, Schroder has the chance to show that he is worth the money he is asking for. Boston would be the perfect team to show that considering the Celtics need a point guard to fill in the void left by Kemba Walker.

Walker was traded to the Oklahoma City Thunder but ended up signing with the New York Knicks.

"I'm proud to announce that for the 2021-22 season I'll be playing for the Boston Celtics!" Schroder said on Instagram. "This is one of the best franchises in NBA history and it will be a honour to put on the green and white and do what I love! I'm going out there every night and leaving it all on the floor for the city!! Who's ready?"

With the Lakers, Schroder averaged 15.4 points and 5.8 assists in 61 games. But his stint with the purple and gold was far from smooth. That was capped by his controversial comments after the Lakers ended their season following their first-round Western Conference loss to the Phoenix Suns.

"You got to go through the bulls--- to get to the good s---," Schroder said at the time.

It will be interesting how Schroder will perform this season as he tries to work on getting a better deal next offseason. Should he respond well and aid the Celtics in their new NBA season drive, that big paycheck could be waiting next summer. But the question is whether that would be close to his $25 million per year dream deal or not.